Complex numbers

Mathematics · Senior school maths · about 10 min

Complex numbers extend ordinary real numbers by including a unit whose square is negative one. They allow equations without real solutions to be solved and make it easier to describe rotations, oscillations and electrical quantities. The two most useful views are algebraic form, which makes arithmetic straightforward, and the complex plane, which makes size and angle visible.

The key idea

Write a complex number in Cartesian form as

z=a+bi,i2=−1,∣z∣=a2+b2.z=a+bi,\qquad i^2=-1,\qquad |z|=\sqrt{a^2+b^2}.

Here aa is the real part, bb is the imaginary part, ii is the imaginary unit, and ∣z∣|z| is the modulus.

Draw perpendicular real and imaginary axes crossing at origin O. In the first quadrant place a point z with coordinate projection a rightward along the real axis and b upward along the imaginary axis, both clearly positive. Connect O to z with a straight diagonal segment marked r. Draw a thin right-angle marker at the corner (a,0), dotted horizontal and vertical projections from z, and a small anticlockwise angle arc from the positive real axis to the segment O-z marked theta. No numeric coordinates.
A complex number is a point in a plane, and its modulus is the distance from the origin.

Try it yourself

Move a point in the complex plane and compare its real part, imaginary part, modulus and argument.

Calculate using algebra

Add or subtract complex numbers by combining real parts and imaginary parts separately. Multiply by expanding brackets and replacing every i2i^2 with −1-1. The conjugate of z=a+biz=a+bi is z‾=a−bi\overline{z}=a-bi, which reflects the point across the real axis. Multiplying a number by its conjugate gives zz‾=a2+b2z\overline{z}=a^2+b^2, a real value. To divide by c+dic+di, multiply the numerator and denominator by c−dic-di. The denominator becomes c2+d2c^2+d^2, so the result can be separated into its real and imaginary parts, provided the denominator is not zero.

Draw a real horizontal axis and imaginary vertical axis with O at their intersection. Place z at (3,2) and z_bar at (3,-2), exactly reflected about the horizontal axis. Draw a thin dotted vertical segment connecting the two points, crossing the real axis at its coordinate 3, and mark their shared projection on the real axis. The points must be equally distant from the real axis. Do not show products, quotients or modulus values.
The conjugate reflects a complex number across the real axis.

Read the complex plane

Plot z=a+biz=a+bi at coordinates (a,b)(a,b), with the real axis horizontal and the imaginary axis vertical. The modulus r=∣z∣r=|z| is its distance from the origin. Its argument θ\theta is the angle measured anticlockwise from the positive real axis. Determine the quadrant before using an inverse tangent: θ=atan2⁡(b,a)\theta=\operatorname{atan2}(b,a) is a reliable calculator expression. A principal argument is commonly chosen in (−π,π](-\pi,\pi]. Numbers in different quadrants can have the same ordinary tangent value but different arguments, so simply entering tan⁡−1(b/a)\tan^{-1}(b/a) can produce a wrong angle.

Use polar form

For z≠0z\ne0, write z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta), where r=∣z∣r=|z| and θ=arg⁡z\theta=\arg z. Polar form makes products easier: multiply moduli and add arguments. For quotients, divide moduli and subtract arguments. For integer powers, de Moivre's result gives zn=rn(cos⁡(nθ)+isin⁡(nθ))z^n=r^n(\cos(n\theta)+i\sin(n\theta)). Angles that differ by an integer multiple of 2π2\pi describe the same complex number. When a question requests the principal argument, convert the angle into the specified principal range. The number zero has modulus zero but no defined argument.

Worked example: Divide two complex numbers

Calculate z=3+4i1−2iz=\frac{3+4i}{1-2i} in the form a+bia+bi. Then find its modulus and its principal argument in radians.

Show the solution
  1. Use the conjugate of the denominator:
z=(3+4i)(1+2i)(1−2i)(1+2i).z=\frac{(3+4i)(1+2i)}{(1-2i)(1+2i)}.
  1. Expand and simplify using i2=−1i^2=-1:
z=3+6i+4i+8i21+4=−5+10i5=−1+2i.z=\frac{3+6i+4i+8i^2}{1+4}=\frac{-5+10i}{5}=-1+2i.
  1. Modulus:
∣z∣=(−1)2+22=5≈2.2361.|z|=\sqrt{(-1)^2+2^2}=\sqrt{5}\approx2.2361.
  1. Principal argument: The point (−1,2)(-1,2) is in quadrant II, so
arg⁡z=π−tan⁡−1(2)≈2.0344 rad.\arg z=\pi-\tan^{-1}(2)\approx2.0344\,\mathrm{rad}.

Answer: z=−1+2iz=-1+2i, ∣z∣=5≈2.2361|z|=\sqrt5\approx2.2361, and arg⁡z≈2.0344 rad\arg z\approx2.0344\,\mathrm{rad}.

Common mistakes

Using i2=1i^2=1 when expanding brackets.

Replace every i2i^2 with −1-1 before collecting terms.

Conjugating the numerator rather than the denominator during division.

Multiply both numerator and denominator by the conjugate of the denominator.

Using inverse tangent without checking the quadrant.

Plot the signs of the real and imaginary parts, or use atan2⁡\operatorname{atan2}.

Assigning an argument to the number zero.

Remember that the zero vector has no direction and therefore no defined argument.

Check your understanding

1. Calculate (2+3i)(1−2i)(2+3i)(1-2i).

2. What is the modulus of −6+8i-6+8i?

3. What is the principal argument of −1−i-1-i?

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